several choices for executable path, but only one works inside Visual Studio?

I am trying to register my executable for some shell action and need to find out the path to current executable. I found several questions (and answers) here on SO, and found the following options:

• Environment.GetCommandLineArgs()[0]
• System.Diagnostics.Process.GetCurrentProcess().MainModule.FileName
• typeof(Program).Assembly.Location

However when debugging inside Visual Studio 2010 the first two return the vshost exe name, e.g. ...bin\Debug\ExportVSProject.vshost.exe. I think I understand why. By trial-and-error I found that the last provides the right name inside VS and outsid开发者_JAVA技巧e.

My question is, are there any downsides to using Assembly.Location? The reason I am asking is I did not see any comparison to choose one over the other in the other answers.

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It's fine. The more general solution is Assembly.GetEntryAssembly().Location, usable anywhere.