Suppress Non-Matching Lines in Grep [closed]

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Closed 11 years ago.

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Running service --status-all | grep "firestarter" in Ubuntu shows the entire output of service --status-all with the text "firestarter" highlighted in red. How do you get grep to only show the line that contains the matched text, and hide everything else?

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Maybe service --status-all writes to stderr, not stdout? Then you can use

service --status-all 2>&1 | grep firestarter

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You must have some weird env variables set. Try this:

service --status-all | `which grep` firestarter

Or:

service --status-all | /bin/grep firestarter

And show the output of env and alias if possible so we can see whats wrong with your grep command.

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For me, I have:

[ 13:55 jon@host ~ ]$ echo $GREP_OPTIONS
--color=always

You probably have something set there, and/or in GREP_COLOR that is causing this.

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if you don't want to use an alias, but the original command, you could try "\cmd". e.g.

service --status-all | \grep "firestarter"