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org.hibernate.MappingException: Unknown entity: java.lang.Long

开发者 https://www.devze.com 2023-04-09 05:05 出处:网络
I am trying to create a named-native-query that returns a Long. Here is my orm.xml file (simplified as much as possible)

I am trying to create a named-native-query that returns a Long.

Here is my orm.xml file (simplified as much as possible)

<?xml version="1.0" encoding="UTF-8"?>
<entity-mappings xmlns="http://java.sun.com/xml/ns/persistence/orm"
  xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
  xsi:schemaLocation="http://java.sun.com/xml/ns/persistence/orm orm_2_0.xsd"
  version="2.0">

<named-native-query name="getCaseNumberByCommId" result-class="java.lang.Long">
  <query>SELECT case_id FROM communications WHERE comm_id =(?1)</query>
</named-native-query>

</entity-mappings>

this is the error I get:

ERROR - org.hibernate.impl.SessionFactoryImpl - Error in named query: getCaseNumberByCommId [coral:launch] org.hibernate.MappingException: Unknown entity: java.lang.Long

I've also tried just specifying "Long"

<named-native-query name="getCaseNumberByCommId" result-class="Long">
  <query>SELECT case_id FROM communications WHERE comm_id =(?1)</query>
</named-native-query>

and strangely get this error:

Caused by: org.hibernate.An开发者_Go百科notationException: Unable to find entity-class: Long ... Caused by: java.lang.ClassNotFoundException: Long

Java can't find Long in java.lang?

Thank you for any clues

edit: I tried removing the 'result-class' annotation :

    <named-native-query name="getCaseNumberByCommId" >
        <query>SELECT case_id FROM communications WHERE comm_id =(?1)</query>
    </named-native-query>

and get this error:

nested exception is org.hibernate.cfg.NotYetImplementedException: Pure native scalar queries are not yet supported

Update*

I never did find a way to do this, but since the database had a uniqueness constraint on comm_id, I was able to just return a mapped pojo object instead of a count.

e.g.

    <named-native-query name="getByCommId" result-class="com.foo.model.Communication">
        <query>SELECT * FROM communications WHERE comm_id =(?1)</query>
    </named-native-query>

and then pull the desired case_id out of the returned pojo.


Without looking into this further the result-class should be one of your mapped entities and because Long is not one of your Entities you're receiving the AnnotationException.

Try removing the result-class from the mapping as it is only used for building queries that return Entity Objects.


Edit:

In regard to: org.hibernate.cfg.NotYetImplementedException: Pure native scalar queries are not yet supported:

After a quick dig around I found this:

https://hibernate.atlassian.net/browse/ANN-661

Where I read:

Workaround is to do such queries using Session.createSQLQuery() or straight JDBC.

There are a couple of examples for such queries here: http://docs.jboss.org/hibernate/core/3.6/reference/en-US/html/querysql.html#d0e17378

i.e

sess.createSQLQuery("SELECT * FROM CATS").list();

sess.createSQLQuery("SELECT ID, NAME, BIRTHDATE FROM CATS").list();

or further down in Example 18.4 http://docs.jboss.org/hibernate/core/3.6/reference/en-US/html/querysql.html#querysql-namedqueries

<sql-query name="mySqlQuery">
    <return-scalar column="name" type="string"/>
    <return-scalar column="age" type="long"/>
    SELECT p.NAME AS name, 
           p.AGE AS age,
    FROM PERSON p WHERE p.NAME LIKE 'Hiber%'
</sql-query>


<named-native-query name="getCaseNumberByCommId">
  <query>SELECT case_id FROM communications WHERE comm_id =(?1)</query>
</named-native-query>

something like this works for me.

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