I have the following (simplified) models in my Django app:
class Color(models.Model):
name = models.CharField(max_length=10)
class Item(models.Model):
name = models.CharField(max_length=200)
color = models.ForeignKey(Color, 开发者_如何学运维blank=True, null=True)
class Favorite(models.Model):
user = models.ForeignKey(User)
item = models.ForeignKey(Item)
I'm currently getting all the items I need using the following query:
favorites = Favorite.objects.filter(user=request.user)
How can I get all the distinct colors for the items in that QuerySet
?
I need the a list of the actual color objects, not just the color ids, which I can get using
favorites.values_list('item__color').distinct
If I understand you correctly, the following should do the trick:
favorites = Favorite.objects.filter(user=request.user)
color_ids = favorites.values_list('item__color', flat=True).distinct()
colors = Color.objects.filter(id__in=color_ids)
There has to be a cleaner way than that though.
Edit: A much cleaner solution:
colors = Color.objects.filter(item__favorite__user=request.user).distinct()
Can you do:
Color.objects.filter(item__favorite__user = request.user).distinct()
You might have to set some related_name
s on your foreign keys if these aren't the defaults (I can never remember the defaults).
Can you do:
favorites = Favorite.objects.filter(user=request.user).distinct('item__color')
The is values_list(*fields, flat=False, named=False)
method, so run it on your objects, for example:
user.groups.values_list('name', flat=True)
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