I am facing an issue with a conditional join.
This is my query :
SELECT table_开发者_运维技巧b.name
FROM table_a
LEFT JOIN table_b
ON table_a.id = table_b.a_id
The description of my table_b :
id, a_id, ref_z, name
----------------------
1 | 0 | 1 | James
2 | 0 | 2 | John
3 | 2 | 2 | John. S
4 | 0 | 3 | Martin
5 | 6 | 3 | Martin. M
6 | 2 | 3 | Martin. M. Mr
Let's say I have a parameter @a_id.
I would like to join table_a and table_b ON table_a.id = @a_id if it exists else on 0.
So the output of the previous query will be (with @a_id = 2) :
James
John. S
Martin. M. Mr
Anyone has an idea, a blog post, a man page or anything else that can lead me to a correct query ?
Thank you,
where a_id = 2
your join can be shorten into using (a_id)
since both columns have the same name and there is no ambiguity.
on / using
should not be confused for your predicate clause (where
)
Assuming you have only one table, this worked for me
DECLARE @t TABLE
(
id int,
a_id int,
ref_z int,
name varchar(50)
)
INSERT INTO @t VALUES (1, 0, 1, 'James'),
(2, 0, 2, 'John'),
(3, 2, 2, 'John. S'),
(4, 0, 3, 'Martin'),
(5, 6, 3, 'Martin. M'),
(6, 2, 3, 'Martin. M. Mr')
DECLARE @a_id int = 2
SELECT COALESCE(table_b.name, (SELECT table_b2.name FROM @t AS table_b2 WHERE table_b2.a_id = 0 ORDER BY table_b2.id LIMIT 1)) AS name
FROM (
SELECT ref_z
FROM @t AS table_z
GROUP BY ref_z
) AS table_z
LEFT OUTER JOIN @t AS table_b ON table_b.ref_z = table_z.ref_z AND table_b.a_id = @a_id
And the results:
James
John. S
Martin. M. Mr
Also note that this will also only display one record (the first) if there are multiple matches for a_id = 0
You could try using IFNULL with a sub select?:
SELECT ifnull(table_b.name,(select s.name from table_a sa inner join table_b sb on sa.a_id = sb.a_id where sb.a_id = 0 limit 1)) as name
FROM table_a
LEFT JOIN table_b
ON table_a.id = table_b.a_id;
Untested I'm afraid but hope it helps!
Also - how do you want to handle multiple rows with a_id = 0? The above will only bring back the first row if there are multiples...
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