I have the开发者_运维技巧 following table structure.
<table id='mytable'>
<tr><td>1</td></tr>
<tr><td>2</td></tr>
<tr><td>3</td></tr>
<tr><td>
<table>
<tr><td>A</td></tr>
<tr><td>B</td></tr>
<tr><td>C</td></tr>
</table>
</td></tr>
</table>
What I want to do is just getting the direct TR
elements from mytable
. Obviously, there are 4 direct TR
of mytable
.
The following shows three statements. I expected they return same result. However they don't.
var mytable$ = $("#mytable");
var trcount1 = mytable$.children("tbody").children().length; // trcount1 = 4
var trcount2 = mytable$.children("tbody > tr").length; // trcount2 = 0
var trcount3 = $("tbody > tr", mytable$).length; // trcount3 = 7
Only the syntax for getting trcount1
is what I wanted.
Why are trcount2
and trcount3
not 4?
Thanks
Alex
===================================
Thanks jfriend00's reply.
That's what I want.
$("> tbody > tr", mytable$).length; // 4
mytable$.find("> tbody > tr").length; // 4
I missed ">" before tbody
.
Inside the browser, your DOM actually looks like this (note the automatic inclusion of the <tbody>
tags):
<table id='mytable'>
<tbody>
<tr><td>1</td></tr>
<tr><td>2</td></tr>
<tr><td>3</td></tr>
<tr><td>
<table>
<tbody>
<tr><td>A</td></tr>
<tr><td>B</td></tr>
<tr><td>C</td></tr>
</tbody>
</table>
</td></tr>
</tbody>
</table>
So, given that, here's how to explain your observations:
var trcount1 = mytable$.children("tbody").children().length; // trcount1 = 4
You're asking for direct children of the table that are tbody
and then the children of that. There is one direct child that is a tbody
and there are four direct children of that tbody
tag so you get 4.
var trcount2 = mytable$.children("tbody > tr").length; // trcount2 = 0
You're asking for direct children of the table (which is only the tbody
object) that also match this selector "tbody > tr"
. Since we're only looking at direct children of the table, this is only the tbody
object itself and the tbody
object iself doesn't match "tbody > tr"
the result is 0 as there are no direct children that match that criteria.
Remember .children()
is direct children only. If you want to consider all children and children of children, then you use .find()
or just put the tag in the main selector.
var trcount3 = $("tbody > tr", mytable$).length; // trcount3 = 7
Here's you're asking for any tr
tag inside of mytable
that has a direct parent that's tbody
. There are seven of those since all tr
tags in mytable
match that criteria.
If you want just the tr
tags in the first table, I would recommend:
$("#mytable > tbody > tr") // will be 4
If you want all the tr
tags in both tables, I would recommend:
$("#mytable tr") // will be 7
If you want just the tr
tags in the second table, I would recommend:
$("#mytable table tr") // will be 3
trcount1
gets all tbody
s that are direct descendants of mytable$
and then gets all direct descendants of that which are your four tr
s.
trcount2
looks for all tr
s that are a direct descendant of a tbody
in the children of mytable$
. The children of mytable$
is only the one tbody
.
trcount3
looks for all tr
s that are a direct descendant of a tbody
in the context of mytable$
. The first four tr
s are direct descendants of a tbody
and the nested tr
s are also direct descendants of a tbody
.
精彩评论