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Include a variable inside a NSString?

开发者 https://www.devze.com 2023-04-08 04:39 出处:网络
This works fine, we all know that: 开发者_运维问答 NSString *textoutput = @\"Hello\"; outLabel.text = textoutput;

This works fine, we all know that:

开发者_运维问答
NSString *textoutput = @"Hello";
outLabel.text = textoutput;

However, what if you want to include a variable inside that NSString statement like the following:

NSString *textoutput =@"Hello" Variable;

In C++ I know when I cout something and I wanted to include a variable all I did was soemthing like this:

cout << "Hello" << variableName << endl;

So I'm trying to accomplish that with Objective-C but I don't see how.


You can do some fancy formatting using the following function:

NSString *textoutput = [NSString stringWithFormat:@"Hello %@", variable];

Note that %@ assumes that variable is an Objective-C object. If it's a C string, use %s, and if it's any other C type, check out the printf reference.

Alternatively, you can create a new string by appending a string to an existing string:

NSString *hello = @"Hello";
NSString *whatever = [hello stringByAppendingString:@", world!"];

Note that NSString is immutable -- once you assign a value, you can't change it, only derive new objects. If you are going to be appending a lot to a string, you should probably use NSMutableString instead.


I have The Cure you're looking for, Robert Smith:

if your variable is an object, use this:
NSString *textOutput = [NSString stringWithFormat:@"Hello %@", Variable];

The '%@' will only work for objects. For integers, it's '%i'.

For other types, or if you want more specificity over the string it produces, use this guide

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