Question about weird pointer

I study C. Digging in some C source code where I f开发者_运维百科ound that line. I have read about pointers, but I did not see such an example.

char   *uppercase (char *s);

What that mean ?

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It's a declaration of a function that takes a char pointer and returns a char pointer.

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That means that the function takes a pointer to a character and returns a pointer to a character i.e the start of the string.

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char   *uppercase (char *s);

is the same as

char* uppercase (char *s);

Its return type is char*; it returns a pointer.

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uppercase is afunction which returns a char type address ( that is, it can be stored in a char pointer ) as its written as char *uppercase... uppercase() takes a char pointer as argument char *s... therefore its written as char *uppercase( char *s).

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In C the location of the * doesn't matter as long as it is somewhere between the type and name. So char* s is the same as char *s and even char * s.

The same applies to functions and their return types, char* uppercase() is equivalent to char *uppercase() and char * uppercase().

White-space is more or less ignored in C so when writing your own code I recommend you pick one format and stick with it.

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The location of the asterisk * can be anywhere: between return type or function name. It is more logical to keep it on the return type's end i.e. char*