I have below macro,getting script out of range error in If arr(0) <> opt Then arr(0) = VAL_DIFF
if i see the length of that array it is showing 2.I dont understand why i am not able to access arr(0),As per i know Array always starts with 0.I able to print arr(1),arr(2) values.
Below macro able to findout similar records and copied to sheet2.Here i also wants to highlight with color in sheet1. Please help me.
Option Base 1
Sub Tester()
Const COL_ID As Integer = 1
Const COL_SYSID As Integer = 2
Const COL_STATUS As Integer = 4
Const COL_OPTION As Integer = 3
Const VAL_DIFF As String = "XXdifferentXX"
Dim d As Object, sKey As String, id As String
Dim rw As Range, opt As String, rngData As Range
Dim rngCopy As Range, goodId As Boolean
Dim FirstPass As Boolean, arr
With Sheet1.Range("A1")
Set rngData = .CurrentRegion.Offset(1).Resize( _
.CurrentRegion.Rows.Count - 1)
End With
Set rngCopy = Sheet1.Range("F2")
Set d = CreateObject("scripting.dictionary")
FirstPass = True
redo:
For Each rw In rngData.Rows
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sKey = rw.Cells(COL_SYSID).Value & "<>" & _
rw.Cells(COL_STATUS).Value
If FirstPass Then
'Figure out which combinations have different option values
' and at least one record with id=US or CHN
id = rw.Cells(COL_ID).Value
goodId = (id = "US" Or id = "CHN")
opt = rw.Cells(COL_OPTION).Value
If d.exists(sKey) Then
arr = d(sKey) 'can't modify the array in situ...
If arr(1) <> opt Then arr(1) = VAL_DIFF
If goodId Then arr(2) = True
d(sKey) = arr 'return [modified] array
Else
d.Add sKey, Array(opt, goodId)
End If
Else
'Second pass - copy only rows with varying options
' and id=US or CHN
If d(sKey)(2) = VAL_DIFF And d(sKey)(1) = True Then
rw.Copy rngCopy
Set rngCopy = rngCopy.Offset(1, 0)
End If
End If
Next rw
If FirstPass Then
FirstPass = False
GoTo redo
End If
End Sub
Stop using Option Base 1 at the top of your modules. It might seem to make things easier, but it only ends up causing confusion. I already gave you the answer to coloring the range - please try to look things up and try them out before posting here.
To check the lower bound position of an array, use Lbound(arr)
.
Also, you did not initialize arr as an array. Initialize it like so:
Dim arr() As Variant
.
You could also specify the lower dimension and upper dimension of the array.
Dim arr(3 To 10) As Variant
. This creates an array of 7 elements starting at position zero. I suggest learning more about arrays in VBA by doing a Google search.
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