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.Net 4: How to reference a dynamic object with property named "return"

开发者 https://www.devze.com 2023-04-07 23:38 出处:网络
I\'m retrieving json from a public api and converting it into a dynamic object using JsonFx. JsonFx.Json.JsonReader reader = new JsonFx.Json.JsonReader();

I'm retrieving json from a public api and converting it into a dynamic object using JsonFx.

JsonFx.Json.JsonReader reader = new JsonFx.Json.JsonReader();
dynamic response = reader.Read(jsonAsString);

The json contains a pr开发者_运维技巧operty named return. e.g.

{"result":"success","return":{"high":{"value":"3.85001","value_int":"385001","display":"3.85001\u00a0\u20ac","currency":"EUR"}}

JsonFx creates the dynamic object fine and I can also debug into it and see the values. The problem is when I try to reference the property in my code the compiler complains:

response.return.high.currency
Identifier expected; 'return' is a keyword  

How can I reference the return property without the compiler complaining?


Try response.@return.high.currency.

You need to append @ at the begining of any field wich name is the same as C# keywords.

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