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Why am I getting a '.class' expected error? Simple Array script

开发者 https://www.devze.com 2023-04-07 19:27 出处:网络
My program is creating an array and allowing the user to input 10 double precision numbers. Then the program will sort them in order from lowest to highest. I have the following but receive .class exp

My program is creating an array and allowing the user to input 10 double precision numbers. Then the program will sort them in order from lowest to highest. I have the following but receive .class expected error upon compiling. Any ideas on why this is happening? Note * I have not been able to compile this yet so I don't even know if this will work. *

import java.io.*;

public class ArrayDemo
{
    public static void main(String[] args) throws IOException
    {
        int i = 0;
        int j = 0;
        int temp = 0;
        double[] intValue = new double[10];
        String[] numbers = {"first", "second", "third", "fourth", "fifth", "sixth", "seventh", "eighth", "ninth", "tenth"};
        int len = intValue.length[];

        BufferedReader dataIn = new BufferedReader (new In开发者_如何学PythonputStreamReader(System.in));

        for (i = 0; i < len; ++i)
            System.out.println("Enter the " + numbers[i] + " number");
        intValue[i] = Double.valueOf(dataIn.readLine());

        {

        for (j = 0; j < (len - 1) -i; j++)
            if (intValue[j] > intValue[j+1]) 
            {
                temp = intValue[j];
                intValue[j] = intValue[j+1];
                intValue[j+1] = temp;
            }

        for (i = 0; i < 10; i++);
        {
            System.out.println("Array after sorting in ascending order");
            System.out.println();
            System.out.println(intValue[i]);

        }

        }
    }
}

Thank you for any input. :)


int temp = 0; should be double temp = 0;

and

int len = intValue.length[]; should be int len = intValue.length;

and

for (i = 0; i < 10; i++); should be for (i = 0; i < 10; i++)

Sample


EDIT

import java.io.*;

public class Main
{
    public static void main(String[] args) throws IOException
    {
        int i = 0;
        int j = 0;
        int k = 0;
        double temp = 0;
        double[] intValue = new double[10];
        String[] numbers = {"first", "second", "third", "fourth", "fifth", "sixth", "seventh", "eighth", "ninth", "tenth"};
        int len = intValue.length;

        BufferedReader dataIn = new BufferedReader (new InputStreamReader(System.in));

        for (i = 0; i < len; ++i) {
            System.out.println("Enter the " + numbers[i] + " number");
            intValue[i] = Double.valueOf(dataIn.readLine());
        }


        for (j = 0; j < len; j++)
        {
            for(k = 0; k < len; k++) {
                if (intValue[j] > intValue[k]) 
                {
                    temp = intValue[j];
                    intValue[j] = intValue[k];
                    intValue[k] = temp;
                }
            }
        }

        System.out.println("Array after sorting in ascending order");
        for (i = 0; i < 10; i++)
        {
            System.out.print(intValue[i] + ", ");

        }

    }
}


int len = intValue.length[];

You don't need [] after length and you also tried to assign int temp to a value in a double array

temp = intValue[j];

Also using an IDE like Eclipse/NetBeans/IntelliJ would definitely help!


int len = intValue.length[];

should instead be:

int len = intValue.length;

Also, some of your bracketing appears to be incorrect. I believe, for example, that you want the following snippet:

for (i = 0; i < len; ++i)  
    System.out.println("Enter the " + numbers[i] + " number");
intValue[i] = Double.valueOf(dataIn.readLine());

Changed to:

for (i = 0; i < len; ++i)
{
   System.out.println("Enter the " + numbers[i] + " number");
   intValue[i] = Double.valueOf(dataIn.readLine());
}

You have a number of other logical errors in your code as well. Let me know, after you work with the code for a while based on the current answers, if you have any specific questions and I will help you further.

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