I have deployed my webservice into Tomcat. The WSDL has got some operations like ViewOptions, but when I ran that, I got this error:
This XML file does not appear to have any style information associated with it. The document tree is shown below.
<soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/">
<soap:Body>
<soap:Fault>
<faultcode>soap:Server</faultcode>
<faultstring>1</faultstring>
</soap:Fault>
</soap:Body>
</soap:Env开发者_运维问答elope>
Why do we get this error?
The message isn't an "error" but rather a warning n need not be solved but ignored. An XML document is a data structure but does not contain any presentation/style information internally. Normally an XML document is used in inter-application communication or as a pure data structure that is then used with additional presentation/style information to display to users.
XML can be applied style by XSLT just as HTML by CSS and the above warning can be eradicated An eg: of applying xls to xml
We don't present xml using xls for RSS, Web Services as they are just used for communication without applying stylesheet rather than meant to be presented to user in browser.
So, everything is fine here.
what worked for my case. I replaced all the links of <a href=".."> ... </a>
with window.open("...link", "_self")
and changed
import {
HashRouter as Router,
} from 'react-router-dom';
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