Here is a portion of some code I am trying to write:
//Choice Based Menu
#include <iostream.h>
#include <conio.h>
int main()
{
char choice;
cout<<"Menu"<<endl<<endl;
cout<<"A. Option A"<<endl;
cout<<"B. Option B"<<endl;
cout<<"C. Option C"<<endl;
cout<<"Q. Quit"<<endl;
cout<<endl<<"Choice:\t";
do
{
choice=getch();
cout<<choice<<"\r";
switch(choice)
{
case 'A':
{
cout<<endl<<"Option A!";
break;
}
case 'B':
{
cout<<endl<<"Option B!";
break;
}
case 'C':
{
cout<<endl<<"Option C!";
break;
}
case 'Q':
{
return 0;
}
default:
{
cout<<endl<<"Invalid Choice! Please try again.";
break;
开发者_JAVA百科 }
}
}while(1);
}
Since the loop continues indefinitely, it waits for another input option after executing the code of the previously chosen option.
Menu
A. Option A
B. Option B
C. Option C
Q. Quit
Choice: A
Option A!
I want the line "Choice: A" to update with the most recently entered option every single time. And I want the output of the previously selected option (Option A!) to be replaced with the output from a newly chosen option.
I tried using '\r' as you may have noticed. That does not work because it gives me a carriage return i.e. it moves back to the beginning of the line. I want it to move back only by one character, and not to the beginning of the line.
This this:
#include <iostream.h>
#include <conio.h>
int main()
{
char choice;
cout<<"Menu"<<endl<<endl;
cout<<"A. Option A"<<endl;
cout<<"B. Option B"<<endl;
cout<<"C. Option C"<<endl;
cout<<"Q. Quit"<<endl;
do
{
choice=getch();
cout << "\r" << "Choice:\t"; // Moved into the loop
switch(choice)
{
case 'A':
{
cout << "Option A!"; // No more endl
break;
}
case 'B':
{
cout << "Option B!";
break;
}
case 'C':
{
cout << "Option C!";
break;
}
case 'Q':
{
return 0;
}
default:
{
cout << "Invalid Choice! Please try again.";
break;
}
}
}while(1);
cout << endl; // New sole endl
}
This is not exactly what you want, but it's the closest one can get with minimal rework.
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