I am working on a personal project and I want to take in userinput that looks like this :
1.0+2.5+3--4
and format it to something like this :
1.0 + 2.5 + 3 - -4
so far I am using the .replace("+") to .replace(" + ") and doing that for all of the operands but the problem is it makes the user input into this:
1.0 + 2.5 + 3 - - 4
Is there a way that I can make it with the negative signs. I want to do this so I could parse the numbers into doubles and add and subtract them later on.
my code for it :
import java.util.Scanner;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class StringMan {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
String check = "-a1 +a2 + a3 +-a5";
check = check.replace("--", "+");
System.out.println(check);
Pattern pattern = Pattern.compile("\\s+");
Matcher matcher = pattern.matcher(check);
boolean expr = matcher.find();
String str = matcher.replaceAll(" ");
System.out.p开发者_运维技巧rintln(str);
}
}
output is:
-a1 +a2 - a3 +-a5
-a1 +a2 - a3 +-a5
the problem is I want the output to look like this: -a1 + a2 - a3 + -a5
In this specific case, you can handle --
by just replacing them with +
:
- Take input as a string from the user
- Remove all white space
- Replace all
--
with+
- Continue parsing as desired
I would recommend using regular expressions and their "group" functionality. I would actually remove all whitespace to make things easier, take it out of the equation, one less thing to deal with. And obviously I would recommend simplifying the string, replacing "--" with "+", "*+" with "*" and so on.
now you can use a regex on your cleaned up string.
Pattern firstPat = Pattern.compile("(((\\+|-)?)\\d+(.\\d+)?)");//for matching the first number, leading sign is optional
Pattern remainingPat = Pattern.compile("(\\+|-)(\\d+(.\\d+)?)");//for remaining numbers, leading sign is mandatory.
Pattern remainingPatWithExtOps = Pattern.compile("(\\*|/|\\+|-)(-?\\d+(.\\d+)?)");//for remaining numbers, accommodating multiply and divide with negative signs(positive signs should have been cleaned out)
Matcher match = firstPat.matcher(inputString);
now you can iterate through the string using the match.find()
method. and then use match.group(1)
to get the sign/operation, and use match.group(2)
to get the number...
So...
Double firstnum;
boolean firstNumSigned = false;
if(match.find())
{
firstNum = Double.parse(match.group(0));// Parsing handles possible sign in string.
//obv check for exceptions during this and double check group num
String tmp = match.group(1);
firstNumSigned = tmp.equals("+") || tmp.equals("-");
}
else
{//no match means the input was probably invalid....
throw new IllegalArgumentException("What the heck were you thinking inputting that?!");
}
match = remainingPat.matcher(inputString);//use our other pattern for remaining numbers
if(firstNumSigned)
{
match.find();//a signed first number will cause success here, we need to ignore this since we already got the first number
}
Double tmpRemaingingNum;
String operation;
while(match.find())
{
operation = match.group(1);
tmpRemainingNum = Double.parse(match.group(2));
//Do what you want with these values now until match.find() returns false and you are done
}
PS: code is not tested, im fairly confident of the regex, but I'm not 100% sure about the grouping brackets on the first pattern.. might need to experiment
Start by replacing -- with +, which is mathematically equivalent. Or start by replacing -- with - -, which would keep - and 4 together.
Check this , Read both strings and integers in between operators like '*,--,-,+" We can read both integers and characters.
public static void main(String[] args) {
// TODO Auto-generated method stub
final Pattern remainingPatWithExt=Pattern.compile("(\\p{L}\\p{M}*)[\\p{L}\\p{M}0-9^\\-.-?_+-=<>!;]*");
String check = "a1+a2+--a7+ a3 +-a5";
Matcher matcher = remainingPatWithExt.matcher(check);
while( matcher.find())
{
System.out.println(matcher.group());
//use matcher.group(0) or matcher.group(1)
}
}
output
a1 a2 a7 a3 a5
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