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PHP Regex: Replace anything that isn't a dot or a digit?

开发者 https://www.devze.com 2023-04-07 03:30 出处:网络
I\'m trying to see if a string is an IP address. Since IPv6 is rolling out it\'s better to support that too, so to make it simple, i just want to replace anything that isn\'t a dot or a number.

I'm trying to see if a string is an IP address. Since IPv6 is rolling out it's better to support that too, so to make it simple, i just want to replace anything that isn't a dot or a number.

I found this regex on stackoverflow by searching:

\d+(?:\.\d+)+

but it does the opposite of what i want. Is it possible to inverse that reg开发者_如何学Cex pattern?

Thanks!


Try the following:

[^.0-9]+

Matches anything that is not a dot or a number


This regex will match anything that isn't a dot or a digit:

/[^\.0-9]/


I might try something like this (untested):
Edit:
Old regex was way off, this appears to do better (after testing):
find: .*?((?:\d+(?:\.\d+)+|))
replace: $1

do globally, single line.

In Perl: s/.*?((?:\d+(?:\.\d+)+|))/$1/sg


Regex shortcuts are case sensitive. I think you were trying to do something like this, but what you want is capital D [\D] = any non-digit.

in php it looks like this:

preg_replace('/[\D]/g', '', $string); 

javascript its like this:

string.replace(/[\D]/g, '');
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