I have a table where I store some data. This data is returned from code.php in a JSON structure' array.
$("#errtable").tablesorter();
$.getJSON("./include/code.php", {key:$('#key').val()}, function(data) {
// append the "ajax'd" data to the table body
$.each(data, function(key) {
$("#errtable > tbody").append("<tr><td>"+data[key].errorcode+"</td><td>"+data[key].errordescription+"</td></tr>");
});
// let the plugin know that we made a update
$("#errtable").trigger("update");
// set sorting column and direction, this will sort on the first and third column
var sorting = [[2,1],[0,0]];
// sort on the first column
$("#errtable").trigger("sorton",[sorting]);
});
The problem is that Firebug shows an error:
o is undefined [Break On This Error] o.count = s[1];
referring to:
function updateHeaderSortCount(table, sortList) {
var c = table.config,
l = sortList.length;
for (var i = 0; i < l; i++) {
var s = sortList[i],
o = c.headerList[s[0]];
o.count = s[1];
o.count++;
}
}
does anybody can he开发者_如何学Pythonlp me to fix this ?
Thank you.
With the following code you insert two cells per row, if I am not mistaken:
$("#errtable > tbody").append("<tr><td>"+data[key].errorcode+"</td><td>"+data[key].errordescription+"</td></tr>");
And try two sort the third column, which does not exist:
// set sorting column and direction, this will sort on the first and third column
var sorting = [[2,1],[0,0]];
Sorting the second and first - and not the third - should fix the error in my opinion
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