I am using Microsoft Visual Studio 2010 on Windowns 7. For some un-understandable reason i keep getting the C2275 error when i try to compile the following code:
#include <stdio.h>
#include <stdlib.h>
typedef struct list_node
{
int x;
struct list_node *next;
}node;
node* uniq(int *a, unsigned alen)
{
if (alen == 0)
return NULL;
node *start = (node*)malloc(sizeof(node)); //this is where i keep getting the error
if (start == NULL)
exit(EXIT_FAILURE);
start->x = a[0];
start->next = NULL;
for (int i = 1 ; i < alen ; ++i)
{
node *n = start;
for (;; n = n->next)
{
if (a[i] == n->x) break;
if (n->next == NULL)
{
n->next = (node*)malloc(sizeof(node));
n = n->next;
if (n == NULL)
exit(EXIT_FAILURE);
n->x = a[i];
n->next = NULL;
break;
}
}
}
return start;
}
int main(void)
{
int a[] = {1, 2, 1, 4, 5, 2, 15, 1, 3, 4};
/*code for printing unique entries from the above array*/
for (node *n = uniq(a, 10) ; n != NULL ; n = n->next)
printf("%d ", n->x); puts("");
return 0;
}
I keep getting this error "C2275: 'node' : illegal use of this type as a开发者_JAVA百科n expression" when i compile. However, i asked one of my friends to paste the same code in his IDE it compiles on his system!!
I would like to understand why the behaviour of the compiler is different on different systems and what influences this difference in behavior.You can't declare a variable node * start
after other code statements. All declarations have to be at the start of the block.
So your code should read:
node * start;
if (alen == 0)
return;
start = malloc(sizeof(*start));
I have no idea why you have **node
there.
You simply need node *start
;
精彩评论