I have a list like this
[0,0,1,1,1,0,0,0,1,1,0,0,1,1,1,1]
and I want to group them and th开发者_运维知识库en find the length of each group. So the result will be like that:
[[2,0],[3,1].....[4,1]]
Use itertools.groupby
:
>>> import itertools
>>> l = [0,0,1,1,1,0,0,0,1,1,0,0,1,1,1,1]
>>> [(len(list(g)), k) for k,g in itertools.groupby(l)]
[(2, 0), (3, 1), (3, 0), (2, 1), (2, 0), (4, 1)]
In [7]: import itertools
In [8]: [[sum(1 for _ in g),v] for v,g in itertools.groupby(l)]
Out[8]: [[2, 0], [3, 1], [3, 0], [2, 1], [2, 0], [4, 1]]
Where l
is your input list.
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