I'm retrieving a timestamp 开发者_如何学Cobject from a database using ResultSet.getTimestamp()
, but I'd like an easy way to get the date in the format of MM/DD/YYYY
and the time in a format of HH:MM xx
. I was tinkering around, it it looks as though I can do such by making use of the Date and/or DateTime objects within Java. Is that the best way to go, or do I even need to convert the timestamp to accomplish this? Any recommendations would be helpful.
....
while(resultSet.next()) {
Timestamp dtStart = resultSet.getTimestamp("dtStart");
Timestamp dtEnd = resultSet.getTimestamp("dtEnd");
// I would like to then have the date and time
// converted into the formats mentioned...
....
}
....
import java.sql.Timestamp;
import java.text.SimpleDateFormat;
import java.util.Date;
public class DateTest {
public static void main(String[] args) {
Timestamp timestamp = new Timestamp(System.currentTimeMillis());
Date date = new Date(timestamp.getTime());
// S is the millisecond
SimpleDateFormat simpleDateFormat = new SimpleDateFormat("MM/dd/yyyy' 'HH:mm:ss:S");
System.out.println(simpleDateFormat.format(timestamp));
System.out.println(simpleDateFormat.format(date));
}
}
java.sql.Timestamp
is a subclass of java.util.Date
. So, just upcast it.
Date dtStart = resultSet.getTimestamp("dtStart");
Date dtEnd = resultSet.getTimestamp("dtEnd");
Using SimpleDateFormat
and creating Joda DateTime
should be straightforward from this point on.
java.time
Modern answer: use java.time, the modern Java date and time API, for your date and time work. Back in 2011 it was right to use the Timestamp
class, but since JDBC 4.2 it is no longer advised.
For your work we need a time zone and a couple of formatters. We may as well declare them static:
static ZoneId zone = ZoneId.of("America/Marigot");
static DateTimeFormatter dateFormatter = DateTimeFormatter.ofPattern("MM/dd/uuuu");
static DateTimeFormatter timeFormatter = DateTimeFormatter.ofPattern("HH:mm xx");
Now the code could be for example:
while(resultSet.next()) {
ZonedDateTime dtStart = resultSet.getObject("dtStart", OffsetDateTime.class)
.atZoneSameInstant(zone);
// I would like to then have the date and time
// converted into the formats mentioned...
String dateFormatted = dtStart.format(dateFormatter);
String timeFormatted = dtStart.format(timeFormatter);
System.out.format("Date: %s; time: %s%n", dateFormatted, timeFormatted);
}
Example output (using the time your question was asked):
Date: 09/20/2011; time: 18:13 -0400
In your database timestamp with time zone
is recommended for timestamps. If this is what you’ve got, retrieve an OffsetDateTime
as I am doing in the code. I am also converting the retrieved value to the user’s time zone before formatting date and time separately. As time zone I supplied America/Marigot as an example, please supply your own. You may also leave out the time zone conversion if you don’t want any, of course.
If the datatype in SQL is a mere timestamp
without time zone, retrieve a LocalDateTime
instead. For example:
ZonedDateTime dtStart = resultSet.getObject("dtStart", LocalDateTime.class)
.atZone(zone);
No matter the details I trust you to do similarly for dtEnd
.
I wasn’t sure what you meant by the xx
in HH:MM xx
. I just left it in the format pattern string, which yields the UTC offset in hours and minutes without colon.
Link: Oracle tutorial: Date Time explaining how to use java.time.
You can also get DateTime object from timestamp, including your current daylight saving time:
public DateTime getDateTimeFromTimestamp(Long value) {
TimeZone timeZone = TimeZone.getDefault();
long offset = timeZone.getOffset(value);
if (offset < 0) {
value -= offset;
} else {
value += offset;
}
return new DateTime(value);
}
LocalDateTime dtStart = rs.getTimestamp("dtStart").toLocalDateTime();
Converts this Timestamp object to a code LocalDateTime. The conversion creates a code LocalDateTime that represents the same year, month, day of month, hours, minutes, seconds and nanos date-time value as this code Timestamp in the local time zone.
since 1.8
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