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selectbox 1 selection controls select box 2 (But with data from mySQL)

开发者 https://www.devze.com 2023-04-05 17:23 出处:网络
How do I control select box 2\'s output based on what is selected in select box 1? If I select Record 1 from Select Box 1, it outputs the Record 1 ID in header. I want to output all Records in Select

How do I control select box 2's output based on what is selected in select box 1?

If I select Record 1 from Select Box 1, it outputs the Record 1 ID in header. I want to output all Records in Select Box 2 with Record 1 ID.

How do I implement this, is my SQL select statement incorrect? Do I need to say something like:

Edit Please delete.

$quer=mysql_query("SELECT DISTINCT projectName, projectID 
                   FROM projects 
                   WHERE clientID=$cat 
                   ORDER BY projectName"); 

Above works.

else { 
  $quer=mysql_query("SELECT DISTINCT projectName, projectID 
                     FROM projects 
                     WHERE projectID = $cat 
                     ORDER BY projectName"); } 

Above doesn't work but I feel I'm close but no cigar?

<?php
@$cat=$_GET['cat'];
if(strlen($cat) > 0 and !is_numeric($cat)) {  
  echo "Data Error";
  exit;
}

$quer2 = mysql_query("SELECT DISTINCT clientName,clientID 
                      FROM clients 
                      ORDER BY clientName"); 

if(isset($cat) and strlen($cat) > 0) {
  $quer = mysql_query("SELECT DISTINCT projectName 
                     FROM projects 
                     WHERE projectID = $cat 
                     ORDER BY projectName"); 
} else {
  $quer = mysql_query("SELECT DISTINCT projectName 
                       FROM projects 
                       ORDER BY projectName"); 
}      
echo "<form method=post name=f1 action='dd-check.php'>";

echo "<select name='cat' onchange=\"reload(this.form)\"><option value=''>Select one</option>";
while ($noticia2 = mysql_fetch_array($quer2)) { 
  if ($noticia2['clientID'] == @$cat) {
    echo "<option selected val开发者_如何学Cue='$noticia2[clientID]'>$noticia2[clientName]</option>"."<BR>";
  } else { 
    echo  "<option value='$noticia2[clientID]'>$noticia2[clientName]</option>";
  }
}
echo "</select>";

echo "<select name='subcat'><option value=''>Select one</option>";
while($noticia = mysql_fetch_array($quer)) { 
  echo  "<option value='$noticia[projectName]'>$noticia[projectName]</option>";
}
echo "</select>";

echo "<input type=submit value=Submit>";
echo "</form>";
?>
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