A way to use all the unqualified names in a C++0x enum class?

The new C++ (C++0x or C++11) has an new kind of enum, an "enum class" where the names are scoped to the enum (among other things).

enum class E {
    VAL1, VAL2
};

void fun() {
    E e = E::VAL1;  // Qualified name
}

I'm wondering, however, if I can selectively use the unqualified name in a certain scope. Something like:

void fun() {
    using E::*;
    E e = VAL1;
    switch (e) {
        case VA开发者_StackOverflow中文版L2: ...

I see I can write using E::VAL1 and get one value. But I don't want to do that for every value of a larger enum.

---

There is no way to do this in C++11. Just in case you are not aware of it - you get the E::Val1 notation even for an unscoped enumeration. For such an enumeration, you have Val1 accessible with and without the use of E::.

But you cannot take a scoped enumeration and selectively make all its enumerators visible in a given scope. It should also be noted that you can not write using E::Val1. The spec explicitly forbids this, your compiler just doesn't reject it yet.

---

This is also something I happen to want, but haven't gotten around to trying to solve. Here's an untested solution. EDIT: I tried it out and it works great! This is my very first C++11 utility macro. Also I added a one-past-the-end enumerator to help extend it to "derived" enumerations.

#define IMPORTABLE_ENUM( TYPENAME, ... ) \
\
struct import_ ## TYPENAME { \
    enum TYPENAME { \
        __VA_ARGS__ \
    }; \
}; \
\
typedef import_ ## TYPENAME :: TYPENAME TYPENAME;

This cannot be imported into a block scope, but defines a base class import_duck to bring the enumerators into a class. Usage:

IMPORTABLE_ENUM ( duck, huey, dewey, louie )

duck d = duck::dewey; // can't use unscoped enumerators here

struct duck_madness : private import_duck { // but inside a derived class
    duck who_did_it() { return huey; } // qualification is unnecessary
}

And since there is only one enum type even among derived classes, no static_cast is ever required.