is this no-op or something else?

#include<stdio.h>

int i;
int increment(int i)
{
    return ++i;
}

i开发者_StackOverflownt main()
{
    for(i=0;i<10;increment(i))
    {
        printf("%d",i);
    }
    return 0;
}

Here output is 000000. i.e. infinite lopp occurs.

I want to know that is this occuring due to no-op as we have no variable to store the value of ++i (returned by increment function) or it is due to something else? .please explain.

---

Yes, it's a no-op. The call to increment doesn't change anything since the value is passed by value.

The local definition of i shadows the global definition. Therefore, only the local definition of i is used and the global definition of i is not affected by the increment which is done on the local copy of the variable.

---

The variable you are incremented is the local copy of the argument passed to increment. You have named both i so I may not be able to be so clear, but the point is that the i within increment is not the same than the one defined globally.