Calloc simple problem

char* lw;
if((lw=(char *)calloc(2, sizeof(char))==0)) 
   printf("Failed to allocate.\n"); 
else 
   printf("a开发者_开发问答llocated %p\n", lw);

I've read manual for calloc, need a quick and brief answer, why does it output NIL? It goes to else, so lw cannot possibly be NIL, then outputs "allocated (nil)"? God's hand? ;)

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Because you are assigning to lw calloc(...) == 0, which is false. You want it the other way around

Replace ==0)) with )==NULL).