I'd like to use LESS stylesheets in a parent and child theme, in which most of the stylesheet information is specified by the parent and the child simply overrides a few files. This is possib开发者_StackOverflowle with the Ruby version of LESS like so:
var parser = new(less.Parser)({
paths: ['.', './lib'], // Specify search paths for @import directives
filename: 'style.less' // Specify a filename, for better error messages
});
but is it possible with the command line compiler lessc
? I'd like to say:
$ lessc --path=".;../parent" style.less
Looking at the lessc source code:
case 'include-path':
options.paths = match[2].split(':')
.map(function(p) {
if (p && p[0] == '/') {
return path.join(path.dirname(input), p);
} else if (p) {
return path.join(process.cwd(), p);
}
});
break;
You can pass multiple paths to lessc. So the correct syntax for your example is:
lessc --include-path=".:../parent" style.less
Marcus
There's a --include-path switch that you can use.
lessc --include-path=./inc/ main.less
Note, it needs to be relative to the path that lessc is executing in.
精彩评论