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Android must have Expandableview whose id is

开发者 https://www.devze.com 2023-04-04 06:15 出处:网络
Your content must have a ExpandableView whose id is attribute is \'android.R.list\' This is the error message I am getting from Logcat. Which is confusing me as my XML is this

Your content must have a ExpandableView whose id is attribute is 'android.R.list'

This is the error message I am getting from Logcat. Which is confusing me as my XML is this

<?xml v开发者_开发知识库ersion="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:orientation="vertical"
    android:layout_width="fill_parent"
    android:layout_height="fill_parent">


        <ExpandableListView
                android:id="@+id/list"
                android:layout_width="fill_parent"
                android:layout_height="fill_parent"/>

</LinearLayout>


try this

<ExpandableListView   
     android:id="@id/android:list"
     android:layout_width="fill_parent"
     android:layout_height="fill_parent"/>

ExpandableListView

when you define id like this @+id/list means that you define an id name list in your application namespace and you can refer to it by @id/list , but @android:id/list means that you are referring to an id define in the android namespace This namespace is the namespace of the framework


In your XML make this android:id="@+id/list" to this android:id="@android:id/list". It will solve your problem.

See this link for more help.

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