Finding a list of files by name given a list of keywords and finding the list of keywords that were not found

The problem: I have a list of keywords like this in file call keywords.txt

141367
141374
141376
141368

and I need to use it to search a large complex folder for any file with any of the keywords in its name. I need a rep开发者_运维问答ort of two different lists.

1. The list of files found that contains any of the keywords in its name.
2. The list of keywords that were never found in any file name.

Help?

---

untested

files=$(find folder_name -type f | fgrep -f keywords.txt)

not_found=$(comm -23 <(sort keywords.txt) <(fgrep -f keywords.txt <<< "$files" | sort)

---

Here's something in bash (ver4+)

#!/bin/bash

filecontent=($(<file))
shopt -s globstar
for file in **
do
    found="0"
    for word in ${filecontent[@]}
    do
       case "${file##*/}" in
         *"$word"* )
            echo "file found: $file with keyword: $w"
            found="1"
            ;;
       esac
    done
    case "$found" in
        "0") echo "No keyword file: $file";;
    esac
done