Using pure JSF to obtain calling page

JSF 1.2-1.2_07-b03-FCS

JSTL 1_1-mr2 (special build)

Java 1.6.0_22-b04

Eclipse 3.6.0 (Helios)

Tomcat 6.0.28 (needs to run also on Weblogic)

IE 7.0.5730.13

Firefox: 6.0

We have page: http://{host:port}/mybase/faces/mypage.jsp...

It is called from multiple external pages via hyperlink, redirect, etc.

We would like to determine the URL of the page that called it (in order to implement a command button "back" button) in a pure "JSF" manner.

We know we can do this:

    FacesContext facesContext = FacesContext.getCurrentInstance();
    ExternalContext externalContext = facesContext.getExternalContext();        
    HttpServletRequest origRequest = 
        (HttpServletRequest)externalContext.getRequest();
    String referrer = origRequest.getHeader("referer"); 

This, however, requires the HttpServletRequest which requires including the servlet-api.jar file.

The question: can this be done in a pure JSF manner and thus, without including the servlet-api.jar file?

Thanks, J开发者_如何学Pythonohn

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This, however, requires the HttpServletRequest which requires including the servlet-api.jar file

This makes no sense. JSF at its own has already a Servlet API dependency. Perhaps you're referring to the compilation error in your IDE because the project isn't associated with a target runtime at all? In that case, please read this carefully: How do I import the javax.servlet API in my Eclipse project?

As to the concrete question, just use ExternalContext#getRequestHeaderMap() to get a mapping of the request headers.

String referrer = externalContext.getRequestHeaderMap().get("referer"); 
// ...