A开发者_开发技巧fter answering about tracemem
recently, I learned about retracemem
. The help for ?retracemem
and the example therein leave me unenlightened.
What does retracemem
actually do and why? It doesn't do what I thought it would do, i.e. point one object to the memory location of another, at least as far as I can tell.
I tried a wizardly invocation like .Internal(inspect())
, which performs no magic for me:
> a = 1:10
> b = a[-1]
> .Internal(inspect(a))
@00000000087AE578 13 INTSXP g0c4 [NAM(2)] (len=10, tl=23336) 1,2,3,4,5,...
> .Internal(inspect(b))
@00000000087AE8E8 13 INTSXP g0c4 [NAM(2)] (len=9, tl=7208) 2,3,4,5,6,...
> retracemem(b,retracemem(a))
> .Internal(inspect(b))
@00000000087AE8E8 13 INTSXP g0c4 [NAM(2)] (len=9, tl=7208) 2,3,4,5,6,...
I think retracemem()
just lets you tag a variable copy, which wouldn't produce a tracemem statement (such as a b
above which is really just a copy of a
sans the first element), as being derived from the same source variable, so you can continue to watch the copies/partial copies propagate and see that they derive from the same source.
For example, how does A's memory get copied/propagated:
> A <- 1:10
> tracemem(A)
[1] "<0x100a2a978>"
> B <- A # Assignment to B doesn't make copy
> C <- A + 1 # Assignment to C makes copy, alters it
tracemem[0x100a2a978 -> 0x1020ebbf0]:
> D <- C + 1 # Assignment to D makes copy, alters it
tracemem[0x1020ebbf0 -> 0x1020ebc98]:
> E <- B + 1 # Assignment to E makes copy, alters it
tracemem[0x100a2a978 -> 0x1020a4208]:
> F <- A[-1] # Assignment to F doesn't make copy?
> G <- F + 1 # Even after altering it?
> retracemem(F, retracemem(A)) # Hint to R that F is really A derived
tracemem[<0x100a2a978> -> 0x1009c5910]:
> G <- F + 1 # Reassignment to G makes copy, alters it
tracemem[0x1009c5910 -> 0x1020a4748]:
But then again, I could be entirely wrong...
精彩评论