I'm trying to make a function that takes in either 1 or 3 parameters, and returns either 1 or 3 values (based on parameters passed).
If 1 parameter is passed then the function uses default values for the other 2 arguments. If 3 parameters are passed then it uses those values.
bool foo( 开发者_运维知识库bool x, int &y = 0, int &z = 0) {
x = true; y = y + 1; z = z + 2;
return x;
}
Is this possible in C++ or am I confused with Java functions.
You can do it with two functions:
bool foo( bool x, int &y, int &z) {
x = true; // this isn't really what it does, is it?
y = y + 1; z = z + 2;
return x;
}
bool foo(bool x)
{
int a = 0, b = 0;
return foo(x,a,b);
}
Any function always returns only 1 value. Returning 2 or more values is not possible directly.
Indirectly, it happens when you pass parameters by reference. Since the two parameters &y
and &z
are passed by references, hence changes to them can be reflected back directly.
You can do this by passing by reference..
by doing so you are making a method that points to a memory location. When that memory location is changed, then your value is changed.
Link http://publib.boulder.ibm.com/infocenter/comphelp/v8v101/index.jsp?topic=%2Fcom.ibm.xlcpp8a.doc%2Flanguage%2Fref%2Fcplr233.htm
You cannot do that this way. You can, however, overload that function with different number of parameters, and return, maybe, a std::vector
or std::list
with the results.
EDIT:
Being more sophisticated, you can use tuples for that:
typedef boost::tuple<bool,int,int> my_data_t;
my_data_t my_tuple(true, 1, 0);
then, you define your function like this:
bool foo( my_data_t & t)
{
t.get<0>() = true;
int& y = t.get<1>();
y = y+1;
int& z = t.get<2>();
z = z+2;
return t.get<0>();
}
and call it this way:
bool result = foo ( my_tuple );
then, out of the function, you'll see my_tuple.get<1>()
(the corresponding to y
) as 2 (1+1).
I am not sure what you are trying to do, but you can kind of return multiple values of different type using boost::tuple
.
boost::tuple<bool, int, int> foo( bool x, int y = 0, int z = 0) {
x = true; y = y + 1; z = z + 2;
return boost::make_tuple(x, y, z);
}
int main() {
boost::tuple<bool, int, int> result = foo(x, 1, 2);
std::cout << boost::get<0>(result) << boost::get<1>(result) << boost::get<2>(result);
}
You could also use boost::optional
, if you only want to return x, if only 1 parameter is passed.
Btw. tuple
is available in C++11 too.
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