I am trying to use VB.Net to upload a file to a Sinatra web service, and I'm not sure how to configure either end. When I run the VB.Net app, sinatra invariably responds with code 404. Here's the VB.Net code, which I converted from another SO post:
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
Dim responseData As String = ""
Dim rdr As FileStream = New FileStream("X:\QueryTxtFiles\Query\CDA Curncy_9_1_2011.fqy", FileMode.Open)
Dim req As HttpWebRequest = DirectCast(WebRequest.Create("http://finqueryserver:9898"), HttpWebRequest)
req.Method = "POST" ' you might use "POST"
req.ContentLength = rdr.Length
req.AllowWriteStreamBuffering = True
Dim reqStream = DirectCast(req.GetRequestStream(), Stream)
Dim inData(rdr.Length) As Byte
' Get data from upload file to inData
Dim bytesRead As Integer = rdr.Read(inData, 0, rdr.Length)
' put data into request stream
reqStream.Write(inData, 0, rdr.Length)
rdr.Close()
Try
req.GetResponse()
Catch ex As Exception
responseData = "An error occurred: " & ex.Message
End Try
' after uploading close stream
开发者_C百科 reqStream.Close()
End Sub
And here is the Sinatra code:
require 'rubygems'
require 'sinatra'
post '/:name/:filename' do
puts "got here"
begin
name = params[:name]
rescue
name = "no name"
end
begin
filename = params[:filename]
rescue
filename = "no filename"
end
end
(I never see "got here".)The Sinatra code is based on tutorials using cURL, which I am not. I've also tried
post "/:filename'
which gives 404 also, and simply
post "/"
which does show "got here", but is obviously useless because I need to deal with the file.
Clearly I'm a newbie at both, this can't be that hard, but I'm not sure what to do.
Thank you.
Ok, well for posterity, here's what I did to get it to work. In the vb.net code, I used:
qry_results = wc.UploadFile("http://192.168.9.81:9898/execfqy", "X:\QueryTxtFiles\Query\CDA Curncy_9_1_2011.fqy")
and in the sinatra file:
post '/execfqy' do
qry_file.write(params[:file][:tempfile].readlines)
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