specific number formatter to a phone number

I want to display the the number in the following format

and the format is "123-开发者_JAVA百科456-7890"

I am using

NSNumberFormatter *formatter = [[NSNumberFormatter alloc] init];
[formatter setNumberStyle:NSNumberFormatterNoStyle];
[formatter setPositiveFormat:@"###-###-####"];
[formatter setLenient:YES];

amountField.text =[formatter stringFromNumber:[NSNumber numberWithDouble:[rxAlertResponse.rxPhoneNo doubleValue]]];
NSLog(@"%@",amountField.text);

I am using the above code to do that but the code is not reflecting ..... and the out put appear as 1234567890 only can any body help how to do that.

---

Use this formatter:

NSNumberFormatter *formatter = [[NSNumberFormatter alloc] init]; 
    //[formatter setNumberStyle:NSNumberFormatterNoStyle];
    //[formatter setPositiveFormat:@"###-###-####"]; 
    [formatter setGroupingSeparator:@"-"];
    [formatter setGroupingSize:4];
    [formatter setUsesGroupingSeparator:YES];
       [formatter setSecondaryGroupingSize:3];
    //[formatter setLenient:YES];
    NSString *num = @"1234567890";
    NSString *str = [formatter stringFromNumber:[NSNumber numberWithInt:[num intValue]]];
    NSLog(@"%@",str); 

---

in that code check the

tempStr = [NSString stringWithFormat:@"1(%@)%@-%@", areaCode, phone1, phone2];

as

tempStr = [NSString stringWithFormat:@"%@-%@-%@", areaCode, phone1, phone2]

in PhoneNumberFormatter.m

---

setPositiveFormat considers '-' separators to be minus signs.

Note: See Number Format Patterns

A work-around is to specify ',' separators and replace them:

NSNumber *phoneNumber = [NSNumber numberWithDouble:[rxAlertResponse.rxPhoneNo doubleValue]];
NSString *text =[formatter stringFromNumber:phoneNumber];
amountField.text = [text stringByReplacingOccurrencesOfString:@"," withString:@"-"];

---

Swift :

let numberFormatter = NumberFormatter()
numberFormatter.groupingSeparator = "-"
numberFormatter.groupingSize = 4
numberFormatter.usesGroupingSeparator = true
numberFormatter.secondaryGroupingSize = 3
let number = "1234567890"
let formattedNumber = numberFormatter.string(from: NSNumber(value: Int(number)!))
print(formattedNumber as Any)