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Generate list of of files (with revision) which belongs to a specific cvs-tag

开发者 https://www.devze.com 2022-12-16 06:11 出处:网络
is there a way to gener开发者_开发技巧ate a list of of files which belongs to a specific cvs-tag with revision.

is there a way to gener开发者_开发技巧ate a list of of files which belongs to a specific cvs-tag with revision.

e.g projectname_a includes following files - file_1 rev 1.1 - file 2 rev 1.40 ...


The most simple solution is to do a checkout with this tag somewhere. Takes a bit of disk space, though. If that bothers you, try what you get with the -p option. If this output contains file names, then you just need to filter them out.


The list will be a little more verbose than what you want but you could simply do:

cvs log -S -N -r projectname_a

or possibly (if you don't have the project checked out):

cvs rlog -S -N -r projectname_a ModuleName

(you can use "." (w/o quotes) as the module name if you want to scan the entire repository)

If you only want the file names without the revision information, add -R.


No need to check anything out - you can use the rls command (remote list). It will give you information in a slightly funny way but it is straightforward to process.

cvs rls <MODULE> -r <TAG> -eR

Here's my script snippet:

for NAME in `cvs rls ${MODULE} -r ${TAG} -eR  | grep -v ^$  | grep -v ^D | sed 's/ /~~/g'`
do

    FIRST_CHARACTER=`echo $NAME | cut -c1,1`
    if [ ${FIRST_CHARACTER} = "/" ] 
    then
        # This is a file
        FILE_NAME=`echo $NAME | awk -F/ '{print $2}'`
        VERSION=`echo $NAME | awk -F/ '{print $3}'`

        echo "${DIR_NAME}/${FILE_NAME},*${VERSION}*"

    else
        # This is a dir
        DIR_NAME=`echo $NAME | awk -F: '{print $1}'`
    fi
done 
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