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sorting a multidimensional array in ruby

开发者 https://www.devze.com 2022-12-16 06:07 出处:网络
I have the following array: [[\"2010-01-10\", 2], 开发者_JAVA技巧[\"2010-01-09\", 5], [\"2009-12-11\", 3], [\"2009-12-12\", 12], [\"2009-12-13\", 0]]

I have the following array:

[["2010-01-10", 2], 开发者_JAVA技巧["2010-01-09", 5], ["2009-12-11", 3], ["2009-12-12", 12], ["2009-12-13", 0]]

I just want to sort it by the second value in each group and return the highest one, like i want to the output to be 12 with the given input above.

update

I might add that I made this into an array using to_a, from a hash, so if there is away to do the same with a hash that would be even better.


To sort by second value

x=[["2010-01-10", 2], ["2010-01-09", 5], ["2009-12-11", 3], ["2009-12-12", 12], ["2009-12-13", 0]]

x.sort_by{|k|k[1]}
=> [["2009-12-13", 0], ["2010-01-10", 2], ["2009-12-11", 3], ["2010-01-09", 5], ["2009-12-12", 12]]


Call the sort method on your hash to sort it.

hash = hash.sort { |a, b| b[1] <=> a[1] }

Then convert your hash to an array and extract the first value.

result = hash.to_a[0][1]


Use this on your hash:

hash.values.max

If you only need the highest element, there is no need to sort it!


If you want the key-value pair with the max value:

hash.max_by {|key, val| val} # => ["2009-12-12", 12]

requires Ruby 1.8.7+

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