Small problem regarding scope in PHP, I can't seem to call the variable $report outside of the while loop. I have tried various things, including return
. This doesn't work, the only two functions that work here are if I echo
the variable $report
inside the loop, or if I print
it. Which I do not want to do, although it solves the problem, but 开发者_开发百科I don't want random gibberish on the user's screen.
I have been looking around for the last 15 or so minutes, and I haven't seen any problems quite like this one on here.
Any help would be appreciated.
<?
require "functions2.php";
require "members.php";
$query = "SELECT MAX(DOCid) as prevDOCid from reports";
$result = mysql_query($query);
while ($row = mysql_fetch_array($result)) {
$prevDOCid = $row[prevDOCid];
$thisDOCid = $prevDOCid+1;
$report = "a"."b".$thisDOCid;
}
echo $report;
?>
You could try to define the variable before the loop, e.g.
$report = "";
while ($row = mysql_fetch_array($result)) {
$report .= "a"."b".$row["prevDOCid"]+1;
}
echo $report;
I hope this helps you!
Edit Use .= not +=
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