How can I get the content of this string surrounded by single-quote

I have a string like this:

SOMETHING='abc.abc.abc'
开发者_开发技巧

How can I extract the content of it ( abc.abc.abc ), inside the single-quotes?

---

$ awk -F"=\047|\047" '/SOMETHING/{print $(NF-1)}' file
abc.abc.abc

---

str="SOMETHING='abc.abc.abc'"
substr=$(echo "$str" | cut -d "'" -f 2)

With bash, you could write

substr=$(cut -d "'" -f 2 <<< "$str")

Or, shell only:

IFS="'"
set -- $str
substr=$2

Or use an array

IFS="'"
fields=($str)
substr=${fields[1]}

---

You should be able to already extract it. Example:

$ cat test.sh 
#!/bin/bash
SOMETHING='abc.abc.abc'
echo $SOMETHING
$ ./test.sh 
abc.abc.abc

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You have tagged this question as shell. So I guess you're able to use regular expressions in grep. Or perhaps you could do something with javascript regular expressions.

this regex would find it

abc\.abc\.abc