function xmlPa开发者_如何学Gorser(xml, projectName) {
var currentIndex = 0;
$(xml).find('entry').each(function(){
if($(this).attr('projectName').toLowerCase() == projectName) {
$previous = $(xml).find('entry')[currentIndex - 1]);
$project = $(this);
$next = $(xml).find('entry')[currentIndex + 1]);
//do something with these objects..
}
currentIndex++;
});
}
Here is some sample code. I have an XML file full of 'entry' elements. Each element has a 'projectName' attribute.
The code basically scans the XML for a project name, like say "Magic Giraffes", returns the XML element matching it, and also the previous & next projects. It works... but I want to know if it's the most efficient way to do it.
See how I'm handling the $previous and $next parts? It's calling the .find() function two more times, and then grabbing elements based on the (-1) and (+1) of the current index. Is there a more efficient way to do this?
assuming that each "entry" are siblings, without other elements inbetween:
$project = $(this);
$previous = $project.prev();
$next = $project.next();
else
$project = $(this);
$previous = $project.prev('entry');
$next = $project.next('entry');
in order to completly "optimize" your code, you can use variable as often as you can:
function xmlParser(xml, projectName) {
var exp = new regexp(projectName, "gi");
var $entries = $('entry', xml).filter(function() {
return exp.test( $(this).attr('projectName'));
});
$entries.each(function(){
$project = $(this);
$previous = $this.prev();
$next = $this.next();
//do something with these objects..
});
}
here the "$entries" variable prevent useless access to the full document, "$this" some parsing/selecting by jquery(but that effect is limited on performance).
edit: I did change the looping / matching method, with the help of the "filter" method. Note: if you are certain there is only one "projectname" in entries, you can get rid of the the "$.each" layer, as then "$entries" becomes "$project" directly
You could try using entry[projectName=...] selector, and have jquery search for the right entry (see: http://api.jquery.com/attribute-equals-selector/ ) however you could have problems with case sensitivity.
When you need the next project, you could use $project.next() (see : http://api.jquery.com/next/ ), same for previous.
Instead of using the find function you can use the prev() and next() functions. Try this out:
$previous = $(this).prev();
$project = $(this);
$next = $(this).next();
You can also pass a selector to those to make sure it only returns the prev/next you want like this:
.prev('entry');
If you're concerned about efficiency, you can try something like this. Once you get a list of 'entry' elements, there's no need to keep searching for them again - everything you need is in the array.
function xmlParser(xml, projectName) {
var entries = $(xml).find('entry');
var previous;
var project;
var next;
$.each(entries, function(index, element)) {
if (element.attr('projectName').toLowerCase() == projectName) {
if (index > 0) {
previous = entries[index - 1];
} else {
previous = null;
}
project = entries[index];
if (index < entries.length - 1) {
next = entries[index + 1];
} else {
next = null;
}
}
});
}
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