Considering :
daList=Range[10]
What I need is the title to be the list name but trying :
ListPlot[daList, PlotLabel -> ToString[daList]]
does not seem to work.
EDIT
"daList" is the Title I want. SORRY for previous my previous lack of precision
EDIT
I yet can`t make any solution work but I think I isolated the problem. The list name is a plotting Function argument. I believe the simple version replicating my problem is like :
list = {1, 2, 3, 4};
naming[list_] := ToString[HoldForm[list]];
naming[list]
an below my "real" code :
sequenceCountPlot[conditionSet_] :=
ListPlot[sequenceCountALL[conditionSet],
plotOptions[
("DisplayNo looking outside filter" <> (ToString[HoldForm[conditionSet]])),
"Number of Display",
"Filter Radius in Cm",
prefCOLORS],
PlotRange -> {{0, 10}, {0, Max@(Max /@ sequenceCountALL[conditionSet])}}, Joined -> True]
Where plotOptions is a function to customize some options (Titles and Colors) and feet the plot with other. Please know that Even with 开发者_开发问答Evaluate[plotOptions] the results remain the same.
Try this:
ToString[HoldForm@daList]
so eg
ListPlot[daList, PlotLabel -> ToString[HoldForm@daList]]
I believe that two the most convenient ways to do this are:
daList = Range[10];
ListPlot[daList, PlotLabel -> "daList"]
ListPlot[daList, PlotLabel -> HoldForm[daList]]
Other possibilities:
ListPlot[daList, PlotLabel -> MakeBoxes[daList]]
ListPlot[daList, PlotLabel -> SymbolName[Unevaluated@daList]]
ListPlot[daList, PlotLabel -> ToString[Unevaluated@daList]]
ListPlot[daList, PlotLabel -> ToString[HoldForm@daList]]
Another possibility:
ListPlot[daList, PlotLabel -> ToString[Unevaluated[daList]]]
may be
ListPlot[daList, PlotLabel -> StringJoin[Map[ToString, daList]]]
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