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Get specific sibling with an index-number

开发者 https://www.devze.com 2023-04-02 12:23 出处:网络
Im working on a banner-slideshow, but working with the navigation i\'ve run into trouble: function slideSwitch(item) {

Im working on a banner-slideshow, but working with the navigation i've run into trouble:

function slideSwitch(item) {
    if(item) {

        //Problem
        var $active = $('#banner div').index(item);
        var $activeImage = $('#banner img').index(item);


    } else {
        var $active = $('#banner div.active');
        var $activeImage = $("img[src$='/images/active.png']");

        if ($active.length == 0) $active = $('#banner div:last');
        if ($activeImage.length == 0) $activeImage = $('#banner img:last');
    }
}
$("#banner img").click(function () {
    slideSwitch($(this));
});

The problem is when clicking on an img in #banner. I want to get the position of the imag开发者_如何学编程e (navigation.indicator) transfered and thereby be able to fade in the selected banner. The problem is here:

    var $active = $('#banner div').index(item);
    var $activeImage = $('#banner img').index(item);

Im not using index() right since I dont get an object selected.. how to do this?

I've also tried with "$('#banner div')[item]" but this still doesnt return an object..


Using [] on a jQuery object returns the underlying HTML node for that position in the list. What you want is to re-wrap that node in jQuery.

Try "$($('#banner div')[item])"

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