Say I 开发者_运维百科have a class with some const reference member variable and I would like to forbid a certain type of construction. So I would declare the according constructor private. Of course, a constructor must initialise all const reference member variables of the class. Doing so, however, results in odd looking code:
class A {
};
class B {
B(const A& a): host(a) {}
private:
B():host(A()) {} // This is ugly and not needed !!
const A& host;
};
Is there another way to prohibit a certain construction type except than declaring the constructor private? I do not want to let the compiler write a constructor for me.
Simply don't define this:
B():host(A()) {} // This is ugly and not needed !!
That is, the following should do what you want to do:
class B {
B(const A& a): host(a) {}
private:
//B():host(A()) {} // This is ugly and not needed !!
const A& host;
};
The idea is if you've defined a constructor that takes parameter(s), then the default constructor is not generated by the compiler. That means, instances of the above class cannot be default created!
B b1; //error - needs default constructor which doesn't exist!
B b2(a); //ok - only way to create an instance!
C++11 solution
In C++11, you can explicity tell the compiler not to generate a particular constructor as:
struct B
{
B(const A &a) {}
B() = delete; //disable
};
Not only that. There is more to it, as explained below:
Now the interesting part
You can also selectively disable constructor(s) for selected types which makes delete
more interesting. Consider this,
struct A
{
A (int) {}
};
Object of this class can be created not only with int
argument, but any type which implicitly converts to int
. For example,
A a1(10); //ok
A a2('x'); //ok - char can convert to int implicitly
B b;
A a3(b); //ok - assume b provides user-defined conversion to int
Now suppose, for whatever reason, I don't want the users of class A
to create objects with char
or class B
, which fortunately or unfortunately can implicitly convert to int
, then you can disable them as:
struct A
{
A(int) {}
A(char) = delete; //disable
A(const B&) = delete; //disable
};
Now here you go:
A a1(10); //ok
A a2('x'); //error
B b;
A a3(b); //error - assume (even if) b provides user-defined conversion to int
Online Demo : http://ideone.com/EQl5R
The error messages are very clear:
prog.cpp:9:5: error: deleted function 'A::A(char)'
prog.cpp:10:5: error: deleted function 'A::A(const B&)'
Just leave it out. As soon as you provide a custom constructor, no other constructor is auto-generated (except for a copy constructor).
If you want to forbid any construction – ending up with a class that has only static members – you can simply declare the constructor as private, and not define it. Such a class is very rarely useful in C++ (since you cannot create instances of it); the only purpose that I can think of is to implement trait classes:
template <typename T>
struct type_to_color {
static char const* value() { return "blue"; }
private:
type_to_color();
};
template <>
struct type_to_color<int> {
// Integers are red!
static char const* value() { return "red"; }
private:
type_to_color();
}
char const* char_color = type_to_color<char>::value();
char const* int_color = type_to_color<int>::value();
However, this is extremely uncommon: trait classes are abundant in C++ but they never declare their constructors as private
, it’s just assumed that everybody knows not to instantiate them.
I'll post the C++11 solution: delete the constructor.
class B {
B() = delete;
B(const A& a): host(a) {}
private:
const A& host;
};
As Konrad Rudolph sayd: as soon you provide a custom constructor, no other constructor is auto-generated (except for a copy constructor).
Therefore, other options are:
Declare the constructor private (so that you can't inherit from your class), but do not provide a definition:
class B {
public:
B(const A& a): host(a) {}
private:
B(); // not implemented!
const A& host;
};
Or in C++11, as R. Martinho Fernandes says:
class B {
public:
B() = delete;
B(const A& a): host(a) {}
private:
const A& host;
};
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