开发者

Convert an xml element whose content is inside CDATA

开发者 https://www.devze.com 2022-12-16 05:12 出处:网络
I have a xml fragment like below <Detail uid=\"6\"> 开发者_开发技巧<![CDATA[ <div class=\"heading\">welcome to my page</div>

I have a xml fragment like below

<Detail uid="6">
    开发者_开发技巧<![CDATA[
    <div class="heading">welcome to my page</div>
    <div class="paragraph">this is paraph</div>
    ]]>
</Detail>

and I want to be able to change the

<div class="heading">...</div> to <h1>Welcome to my page</h1>
<div class="paragraph">...</div> to <p>this is paragraph</p>

do you know how I can do that in xslt 1.0


What about running two transforms.

Pass 1.)

<?xml version="1.0" encoding="UTF-8"?>
  <xsl:stylesheet
   version="1.0"
   xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:output method="xml" indent="yes" encoding="UTF-8"/>

  <xsl:template match="/">
    <xsl:apply-templates />
  </xsl:template>

    <xsl:template match="Detail">
        <Detail>
            <xsl:copy-of select="@*"/>
        <xsl:value-of select="." disable-output-escaping="yes" />
        </Detail>
    </xsl:template>

</xsl:stylesheet>

Will produce:

<?xml version="1.0" encoding="UTF-8"?>
<Detail uid="6"> 
    <div class="heading">welcome to my page</div>
    <div class="paragraph">this is paraph</div>
</Detail>

Pass 2.)

<?xml version="1.0" encoding="UTF-8"?>
  <xsl:stylesheet
   version="1.0"
   xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:output method="xml" indent="yes" encoding="UTF-8"/>

  <xsl:template match="/">
    <xsl:apply-templates />
  </xsl:template>

    <xsl:template match="@*|node()">
        <xsl:copy>
            <xsl:apply-templates select="@*| node()" />
        </xsl:copy>
    </xsl:template>

    <xsl:template match="div[@class='heading']">
        <h1><xsl:value-of select="."/></h1>
    </xsl:template>

    <xsl:template match="div[@class='paragraph']">
        <p><xsl:value-of select="."/></p>
    </xsl:template>

</xsl:stylesheet>

Produces:

<?xml version="1.0" encoding="UTF-8"?>
<Detail uid="6">
<h1>welcome to my page</h1>
<p>this is paraph</p>
</Detail>


You cannot tell XSL 1.0 to fish a string out of a CDATA and parse it as XML.


You can't "remove" the CDATA, but you can achieve the desired output somewhat crudely:

<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
   <Detail>
        <xsl:variable name="before" select="substring-before(//Detail,'&lt;div class=&quot;heading&quot;&gt;')" />
        <xsl:variable name="afteropen" select="substring-after(//Detail,'&lt;div class=&quot;heading&quot;&gt;')" />
        <xsl:variable name="body" select="substring-before($afteropen, '&lt;/div&gt;')" />
        <xsl:variable name="after" select="substring-after($afteropen, '&lt;/div&gt;')" />
        <xsl:value-of select="concat($before, '&lt;h1&gt;', $body, '&lt;/h1&gt;',$after)"
                disable-output-escaping="yes"       />
   </Detail>
</xsl:template>
</xsl:stylesheet>

This will work for the first type of div you're trying to parse and you can follow something similar with the second one. It could be made more generic with some effort.

0

精彩评论

暂无评论...
验证码 换一张
取 消

关注公众号