Is there a better way of doing this without having the repeated sub queries that just select a different field?
SELECT Name, er.DateEventStarts, e.LocationName,
(SELECT count(*) FROM Ticket t WHERE t.Deleted = 0 AND Refunded = 0 AND t.EventRepetitionID = e开发者_运维知识库r.EventRepetitionID) AS NoOfAttendees,
(SELECT sum(t.TicketTotalCost) FROM Ticket t WHERE t.Deleted = 0 AND Refunded = 0 AND t.EventRepetitionID = er.EventRepetitionID) AS NoOfAttendees,
(SELECT sum(t.OnlinePayFee) FROM Ticket t WHERE t.Deleted = 0 AND Refunded = 0 AND t.EventRepetitionID = er.EventRepetitionID) AS OnlinePayFee,
(SELECT sum(t.OnlinePayTotalCost) FROM Ticket t WHERE t.Deleted = 0 AND Refunded = 0 AND t.EventRepetitionID = er.EventRepetitionID) AS OnlinePayTotalCost
FROM [Event] e
JOIN EventRepetition er ON er.EventRepetitionID = (SELECT TOP 1 EventRepetitionID FROM EventRepetition er2 WHERE er2.EventID = e.EventID)
As you can see the sub queries are almost the same but just sum or count a different row. I feel there must be a better way of doing this but can't see how else to do it. I imagine this is probably not very efficient.
I apologise if this has already been answered but I just cannot think of a way to describe this problem so was unable to search for a solution.
This might do the trick:
SELECT
Name,
er.DateEventStarts,
e.LocationName,
t.NoOfAttendees,
t.TotalTickets,
t.OnlinePayFee,
t.OnlinePayTotalCost
FROM [Event] e
JOIN EventRepetition er
ON
er.EventRepetitionID = (SELECT TOP 1 EventRepetitionID FROM EventRepetition er2 WHERE er2.EventID = e.EventID)
join
(select EventRepetitionID,COUNT(*),SUM(TicketTotalCost),SUM(OnlinePayFee),SUM(OnlinePayTotalCost)
from Ticket
where Deleted = 0 and Refunded = 0
group by EventRepetitionID) t (EventRepetitionID,NoOfAttendees,TotalTickets,OnlinePayFee,OnlinePayTotalCost)
on
er.EventRepetitionID = t.EventRepetitionID
This should only scan the ticket table once.
Not tested the next one, but it will be something like this:
select Q.name, Q.ateEventStarts, Q.locationName,
count(*), sum(T.TicketTotalCost), sum(T.TicketTotalCost),
sum(T.OnlinePayFee), sum(T.OnlinePayTotalCost)
from (
select Name, er.DateEventStarts, e.LocationName, er.EventRepetitionID
from Event e JOIN EventRepetition er on er.EventRepetitionID =
(select top 1 EventRepetitionID from
EventRepetition er2 where er2.EventID = e.EventID) ) Q
left outer join Ticket T
on t.Deleted = 0 and T.Refunded = 0
and t.EventRepetitionID = Q.EventRepetitionID
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