How can I extract hyphenated strings from this stri开发者_StackOverflow中文版ng line?
ADW-CFS-WE CI SLA Def No SLANAME CI Max Outage Service
I just want to extract "ADW-CFS-WE" from it but has been very unsuccessful for the past few hours. I'm stuck with this simple regEx "(.*)" making the all of the string stated about selected.
You can probably use:
preg_match("/\w+(-\w+)+/", ...)
The \w+
will match any number of alphanumeric characters (= one word). And the second group ( )
is any additional number of hyphen with letters.
The trick with regular expressions is often specificity. Using .*
will often match too much.
$input = "ADW-CFS-WE X-Y CI SLA Def No SLANAME CI Max Outage Service";
preg_match_all('/[A-Z]+-[A-Z-]+/', $input, $matches);
foreach ($matches[0] as $m) {
echo $matches . "\n";
}
Note that this solutions assumes that only uppercase A-Z can match. If that's not the case, insert the correct character class. For example, if you want to allow arbitrary letters (like a and Ä), replace [A-Z]
with \p{L}
.
Just catch every space free [^\s] words with at least an '-'.
The following expression will do it:
<?php
$z = "ADW-CFS-WE CI SLA Def No SLANAME CI Max Outage Service";
$r = preg_match('#([^\s]*-[^\s]*)#', $z, $matches);
var_dump($matches);
The following pattern assumes the data is at the beginning of the string, contains only capitalized letters and may contain a hyphen before each group of one or more of those letters:
<?php
$str = 'ADW-CFS-WE CI SLA Def No SLANAME CI Max Outage Service';
if (preg_match('/^(?:-?[A-Z]+)+/', $str, $matches) !== false)
var_dump($matches);
Result:
array(1) {
[0]=>
string(10) "ADW-CFS-WE"
}
精彩评论