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java.io.File(parent, child) does not work as expected

开发者 https://www.devze.com 2023-04-01 15:43 出处:网络
I am trying to construct a Java File object based on a user provided file name (could be absolute or relative) and a environment dependent base directory. The java doc for java.io.File(File parent, St

I am trying to construct a Java File object based on a user provided file name (could be absolute or relative) and a environment dependent base directory. The java doc for java.io.File(File parent, String child) says the following:

If the child pathname string is absolute then it is converted i开发者_如何学Cnto a relative pathname in a system-dependent way.

That made me think that if I have the following code:

public class TestClass {
    public static void main(String[] args) throws IOException {
        File file = new File(new File("C:/Temp"),"C:/Temp/file.txt");
        System.out.println(file.getAbsolutePath());
    }
}

the output would be

C:\Temp\file.txt

and then I'd be in business because it would not really matter anymore if the user provided an absolute or relative path. But in fact, the output is

C:\Temp\C:\Temp\file.txt

Which means I have to figure out the exact relative path (or at least test different options to see if the file exists). Am I misunderstanding the JavaDoc?


If the child pathname string is absolute then it is converted into a relative pathname in a system-dependent way.

I assume this means that even if you provide an absolute path, it will be converted to (in a system dependent way), and treated as, a relative path.

Which means I have to figure out the exact relative path (or at least test different options to see if the file exists).

Yes, I believe so.

This could perhaps be easily done with

file.getAbsolutePath().startsWith(parent.getAbsolutePath());

to check if it is an absolute path to a directory in parent, and

file.getAbsolutePath().substring(parent.getAbsolutePath().length());

to get the relative part.


With your base directory expressed as a Path, e.g.

Path basePath = new File("C:/Temp").toPath();

you can use Path.resolve to determine the Path (or File) for your fileName, regardless of whether it is absolute or relative:

Path path = basePath.resolve(fileName).normalize();
File file = path.toFile();

The additional normalize here simply takes care of cleaning up any . or .. from the path.

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