开发者

What do these two C warnings mean exactly?

开发者 https://www.devze.com 2023-04-01 13:40 出处:网络
开发者_StackOverflow中文版have the following C code: typedef void*(m3_func)(void); #define NULL ((void*)0)

开发者_StackOverflow中文版have the following C code:

typedef void*(m3_func)(void);
#define NULL ((void*)0)

char* lolinfo()
{
    return "You got the additional info! :D";
}

m3_func** m3_funcs() {
    return (m3_func**) {
        (m3_func*)(&lolinfo), // warning #1
        NULL
    }; // warning #2
}

I'm getting these warnings:

  • /home/lk/proj/m3/m3_lolauncher/lolauncher.c(0,0): Warning: initialization from incompatible pointer type (m3_lolauncher)
  • /home/lk/proj/m3/m3_lolauncher/lolauncher.c(0,0): Warning: excess elements in scalar initializer (m3_lolauncher)

I dont understand the first one as i cast correctly?

I've never seen the second one...


it seems your sample code is not valid C.

if i understand your code, the m3_funcs() function should return a NULL terminated array of function pointers. you are actually trying to use an initializer ({...}) to declare an array and return it right away. but i don't think you can use an initializer outside of a variable declaration... also, note that this "variable" would exists only in the context of the m3_funcs() call, so the address that might eventually be returned would no more be valid after the function has returned.

the correct way to implement such a feature is to have a static global variable, and return its address:

static m3_func *m3_funcs_array[] = {(m3_func *)&lolinfo, NULL};

m3_func ** m3_funcs()
{
    return &m3_funcs_array;
}


A list initialization would be:

a = { b,c,d }

What you are doing here is using the new universal initialization (x{y}). Hence, you're trying to initialize a single m3_func** pointer with two m3_func* pointers. Ergo you have two warnings:

  1. initialization from incompatible pointer type ( m3_func** != m3_func* )
  2. excess elements in scalar initializer ( a pointer is a scalar, and you're trying to initialize it with two pointers -- ergo one excessive )
0

精彩评论

暂无评论...
验证码 换一张
取 消