<?php
$pathname = "http://myserver.com/projects/" . $_GET['project'] . "/";
if ($handle = opendir($pathname)) {
while (false !== ($file = readdir($handle))) {
if ($file != "." && $file != ".." && (strpos($file, '.jpg',1)) ) {
$photo= $pathname . $file;
echo "<image src=\"" . $file . "\">";
}
}
cl开发者_开发知识库osedir($handle);
}
?>
There is my code. All I'm trying to do is pass a URL parameter like "project=Flowers", and have PHP open a folder called /flowers/ and return ALL of the .jpg images inside it.
However, when I run my code, I get these errors:
**Warning: opendir() [function.opendir]: URL file-access is disabled in the server configuration in /nfs/c01/h03/mnt/73283/domains/myserver.com/test.php on line 3
Warning: opendir(http://myserver.com/projects/flowers/) [function.opendir]: failed to open dir: no suitable wrapper could be found in /nfs/c05/h02/mnt/76383/domains/kulthouse.com/html/staging/work.php on line 3**
Any ideas why this won't work??
Any ideas why this won't work??
Because you're using filesystem function to access a web URL
So, I'd make it
$_SERVER['DOCUMENT_ROOT'].'/projects/'.basename($_GET['project']).'/'
basename() is very important here, not letting anyone to browse any directory on your disk
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