how do I parse a url with php

I need to parse a URL in php for a facebook like button. what I do now is this:

<?php
  echo curPageURL();
?>

but I have articles that are sometimes 2 or three pages long so I want to parse the url without the page number so that the like button is for the first page of the article. Sometimes a page number does not exist either.

my url looks like this http://www.mydomain.com/23/My-Article-Title/2/

the 2 at the end is the page number indicating page 2. page one of the article appears like this though

http://www.mydomain.com/23/My-Article-Title/

how do I parse the url in php to remove the page number if it exists?

so I wou开发者_开发百科ld only want to parse it if there was a page number.

---

 preg_replace('=\d+/$=', '', $url);

---

You can use a regular expression with preg_replace:

echo preg_replace('#/[0-9]+(/)?$#', '/', 'http://www.mydomain.com/23/My-Article-Title/34/');

// output: http://www.mydomain.com/23/My-Article-Title/ 

The above regex removes any / + numbers + (optional) / that appears at the end of the URI.

---

Try to use:

 preg_replace('/^(.+[a-zA-Z]\/)[\d]*\/?$/i', '\\1', $str);

---

$url = 'http://www.mydomain.com/23/My-Article-Title/2/';
$url_info  = parse_url($url);
$pathes = (empty($url_info['path']) ? array() : explode('/', trim($url_info['path'], '/')));

if (($len = count($pathes)) > 0  && is_numeric($pathes[$len-1]) )
{
    echo "<pre>";
    print_r($pathes);
    echo "</pre>";
}
?>