I have this array $output which looks like this:
Array(
[0] => Array(
[0] => 1a
[1] => 1b
[2] => 1c
)
[1] => Array(
[0] => 2a
[1] => 2b
[2] => 2c
)
[2] => Array(
[0] => 3a
[1] => 3b
[2] => 3c
)
[3] => Array(
[0] => 4a
[1] => 4b
[2] => 4c
)
)
and so on...
When I want to remove the second element I just use:
$output = unset($output[1]);
to get the following:
Array(
[0] => Array开发者_高级运维(
[0] => 1a
[1] => 1b
[2] => 1c
)
[1] => Array(
[0] => 3a
[1] => 3b
[2] => 3c
)
[2] => Array(
[0] => 4a
[1] => 4b
[2] => 4c
)
)
My question is how to remove every second element of every element in the array ([0][1], [1][1], [2][1], [3][1] ,...) to get the following:
Array(
[0] => Array(
[0] => 1a
[1] => 1c
)
[1] => Array(
[0] => 2a
[1] => 2c
)
[2] => Array(
[0] => 3a
[1] => 3c
)
[3] => Array(
[0] => 4a
[1] => 4c
)
)
Can't be done with a simple command, but you can use a loop:
foreach(array_keys($output) as $key) {
unset($output[$key][1]);
}
Clean and neat:
$f = function(&$a,$k) { unset($a[1]); };
array_walk($arr, $f);
Or:
array_walk($arr, function (&$a, $k) {
unset($a[1]);
});
You can iterate over the array, and unset()
what you want in each sub-array:
foreach($output as &$item) {
unset($item[2]);
}
unset($item); // unset reference
You'd use a combination of array_map
and array_splice
:
function removeSecond( array &$arr )
{
array_splice( $arr, 1, 1 );
}
$out = array_map( 'removeSecond', $input );
The problem with unset
is that it will leave the indexes as they were:
$ php -r '$arr = array(array(0,1,2)); unset($arr[0][1]); var_dump($arr);'
array(1) {
[0]=>
array(2) {
[0]=>
int(0)
[2]=>
int(2)
}
}
While splice will update the indexes:
$ php -r '$arr = array(array(0,1,2)); array_splice($arr[0], 1, 1); var_dump($arr);'
array(1) {
[0]=>
array(2) {
[0]=>
int(0)
[1]=>
int(2)
}
}
foreach($array as $key=>$val){ unset($val[1]); }
I use this:
public function array_unset_key_in_children($array, $keyToUnsetInChildren)
{
$newArray = [];
foreach($array as $key=>$subArray) {
unset($subArray[$keyToUnsetInChild]);
$newArray[$key] = $subArray;
}
return $newArray;
}
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