<?php
$json = file_get_contents('http://tiny.cc/ttrhelp');
$obj = json_decode($json);
$example = $obj->rooms->displayName;
?>
Name: <?php echo $example; ?>
Trying开发者_开发知识库 to show the value for 'displayName' but its not showing
Untested code:
<?php
$json = file_get_contents('http://pub.tapulous.com/tapplications/coresocial/v1/chat/api/index.php?method=room_list');
$obj = json_decode($json);
foreach($obj->rooms as $room){
$example = $room->displayName;
echo $example;
}
?>
You probably want $obj->rooms[0]->displayName
.
CodePad.
echo $obj->rooms[2]->displayName;
Try
echo $obj->rooms[0]->displayName;
精彩评论