Total newbie question here...Today while trying to calculate sum of a list of integers(actually BitSe开发者_StackOverflow社区t), I ran into overflow scenarios and noticed that the return type of(sum/product) is Int. Are there any methods in Range/List to sum up or say multiply all values to Long?
val x = 1 to Integer.MaxValue
println(x.sum) //prints -1453759936
thanks
Convert the elements to Long (or BigInt should that go that far) while summing:
x.view.map(_.toLong).sum
You can also go back to fold
x.foldLeft(0L)(_ + _)
(Note: should you sum over a range, maybe it would be better do a little math, but I understand that is not what you did in fact)
Compare:
>> val x = 1 to Int.MaxValue
x: scala.collection.immutable.Range.Inclusive with scala.collection.immutable.Range.ByOne = Range(...)
With:
>> val x = 1L to Int.MaxValue
x: scala.collection.immutable.NumericRange.Inclusive[Long] = NumericRange(...)
Note that the first uses Int.to
, and the latter used Long.to
(where Int.MaxValue is up-converted automatically). Of course, the sum of a consecutive integer sequence has a very nice discrete formula :)
Happy coding.
This isn't very efficient, but the easiest way:
val x = 1L to Int.MaxValue
println(x.sum) //prints 2305843008139952128
If you need x to contain Ints rather than Longs, you can do
val x = 1 to Int.MaxValue
println(x.foldLeft(0L)(_+_))
Range.Long(1, Int.MaxValue, 1).sum
精彩评论