def rot_dig(x):
y=''
output=[x]
listing=list(x)
for i in range(1,len(x)):
listing.append(listing[0])
开发者_Python百科 del(listing[0])
for i in listing:
y=y+i
output.append(y)
y=''
return output
import math
def prime_is(x,prime):
for m in prime:
if m<=math.sqrt(x):
if x%m==0:
return False
else:
return True
prime=[2]
for x in range(3,1000000):
if prime_is(x,prime):
prime.append(x)
primestr=[]
for x in prime:
primestr.append(str(x))
sums=0
for x in primestr:
count=0
for y in rot_dig(x):
if y in primestr:
count+=1
if count==len(x):
sums+=1
else:
for y in rot_dig(x):
if y in primestr:
primestr.remove(y)
print sums
When run with the bold code the solutions miss the final rotation. So if it looks at say 1193, it includes 1193, 3119, 9311 but not 1931. I have spent a while trying to work out why but I don't get it.
I have since edited the code to make it much quicker and solved the problem I had by simply removing the block of code, but I can't understand why it happens since surely that block of code will only be executed on non circular primes.
It's probably because your outer loop is for x in primestr:
and the marked code removes items from primestr
. You don't want to change primestr
while looping over it that way. You could use a loop like while i < len(primestr)
instead.
Some other improvements would be to compute sqrt
outside the loop; to use a list comprehension instead of a loop to create primestr
; and especially to use string slicing in rot_dig
, it's way more complicated than it needs to be.
精彩评论